2b^2+7b-94=-9

Solution for 2b^2+7b-94=-9 equation:

2b^2+7b-94=-9

We move all terms to the left:

2b^2+7b-94-(-9)=0

We add all the numbers together, and all the variables

2b^2+7b-85=0

a = 2; b = 7; c = -85;
Δ = b2-4ac
Δ = 72-4·2·(-85)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-27}{2*2}=\frac{-34}{4}
=-8+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+27}{2*2}=\frac{20}{4}
=5
$